nawa..this is quite difficult..and to say a nigerian mom was complaining about the kind of questions give to her primary ward..let her come and see the one that has leg
00000000000000000000000 ..Linda you go go ask Cheryl o . We dey here dey suffer news about the Xenophobic attacks you dey tell us about Cheryl BDay. Abeg when you find the answer let me know so I can come chop cake on her Bday
looool thiss was also sent to us by a teacher in my school.. People have come up with Possible answers though buh me i think it's between May 19 and June 18....
buh also a student came up with evidence as to why he thinks it's July 16....
If Cheryl had told Bernard that her birthday fell on the 14th of the month, then he could not have worked out the date at this stage.
However, as he states that he now knows the date, we can rule out July 14 or August 14.
This leaves just three dates to chose from - July 16, Aug 15 and Aug 17.
Following Bernard's statement, Albert is then apparently able to deduce the date of Cheryl's birthday.
This means her birthday must be the only remaining date in the month he was originally told. Given that there are two dates left in August and one in July, it has to be the July date.
May and June are ruled out by the first statement, as Albert knows that Bernard can't identify the month from his date so it is not 18/19. He can only know this because it is not May or June.
Bernard can use Albert's statement, as we can, to rule out May and June - so his Day must be 14, 15, 16 or 17. Bernard knows that Albert couldn't previously rule out 14 but can now. So 15,16,17 left.
I'm afraid I took a shortcut rather than thinking and scanned upwards in my grid for "what's different" forgetting that Bernard's missing information is the month. So yes, 16 is the only remaining day that uniquely identifies a month Ans is July 16
Remember, Albert is told either May, June, July or August.
Bernard is told either 14, 15, 16, 17, 18 or 19
Let’s go through it line by line.
Albert: I don’t know when Cheryl’s birthday is, but I know that Bernard doesn’t know too.
All Albert knows is the month, and every month has more than one possible date, so of course he doesn’t know when her birthday is. The first part of the sentence is redundant.
The only way that Bernard could know the date with a single number, however, would be if Cheryl had told him 18 or 19, since of the ten date options only these numbers appear once, as May 19 and June 18.
For Albert to know that Bernard does not know, Albert must therefore have been told July or August, since this rules out Bernard being told 18 or 19.
Line 2) Bernard: At first I don’t know when Cheryl’s birthday is, but now I know.
Bernard has deduced that Albert has either August or July. If he knows the full date, he must have been told 15, 16 or 17, since if he had been told 14 he would be none the wiser about whether the month was August or July. Each of 15, 16 and 17 only refers to one specific month, but 14 could be either month.
Line 3) Albert: Then I also know when Cheryl’s birthday is.
Albert has therefore deduced that the possible dates are July 16, Aug 15 and Aug 17. For him to now know, he must have been told July. Since if he had been told August, he would not know which date for certain is the birthday.
First we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month. From the first statement, we know that Albert is sure that Bernard doesn't know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn't know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can't know).
Since Albert subsequently can also be sure of the date, he must know it's July. If it's August, he can't be sure as there is August 15 and 17.
Chineke, this question is kinda hard for primary school kids. Its pure logic that gets you thinking and if you are not that smart you may not b able to figure it out. Anyways the correct ans is july 16. Linda you can thank me later for the ans.
Chineke, this question is kinda hard for primary school kids. Its pure logic that gets you thinking and if you are not that smart you may not b able to figure it out. Anyways the correct ans is july 16. Linda you can thank me later for the ans.
First we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
From the first statement, we know that Albert is sure that Bernard doesn’t know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn’t know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can’t know).
Since Albert subsequently can also be sure of the date, he must know it’s July. If it’s August, he can’t be sure as there is August 15 and 17.
The days ranges from 14 to 19, with 18 and 19 appearing only once. So if Cheryls B-day is either 18 or 19 then Benard will know because Cheryl told him the day.
If Cheryl has told Albert her birth month was may or june, it is possible that her B-day will be June 18 or May 19. So if Albert is sure that Benard does not know means that Cheryls told Albert that her B-day is either August or July.
Benard did not know before, but how comes he knows now; after Albert has spoken.
I have 5 dates left in July and August from my solution, Thats 14 to 17 with 14 appearing two times. (July 14, July 16, August 14, August 15, August 17).
So Benard will not know the date of Cheryl B-day if she told him 14. So the day is not 14.
I have 3 dates left (July 16, August 15, August 17).
Since Benard spoke, Albert now knows Cheryl B-day, If Cheryl had told Albert her B-day was in August then Albert would not know because there are two possible dates in August ..
Albert knows the month and Bernard knows the day, and at first they dont know the birthday, it's safe to knock off the months of may and June because since Bernard knows the day, it will be easy to choose may 19 or June 18 because the numbers 18 and 19 appear just once in the days given.
Bernard now says he knows the birthday, which strikes of July 14 and august 14. Because if he was given 14 as the day he will still be confused as there is July 14 and august 14, knowing full well he was given just the day.
Lastly, Albert says he knows the birthday too, which strikes of august because there are 3 days in august and would have still been confused, as he wasn't given the day and may have to choose between the three days in august.
What is left is July 16th. That's Cheryl's birthday!!
July 16th Bernard can only know initially if he has been given a date number which is unique namely 18th or 19th
But you can rule out May and June (the months containing 18th and 19th) immediately because Albert says Benard cannot know. So it must be July or August and based on this
Based on this , Bernard says he now knows. That means it has to be July 16th, August 15th or August 17th. if it was 14th, he would need to know the month to know the date so we can rule out 14th
Based on this Albert says he too knows, which means It cannot be August 15th or 17th (if it were, he would need to know the date number as well). So it must be July 16th
First we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
From the first statement, we know that Albert is sure that Bernard doesn’t know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn’t know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can’t know).
Since Albert subsequently can also be sure of the date, he must know it’s July. If it’s August, he can’t be sure as there is August 15 and 17.
The answer is July 16, after eliminating logically.
First, if Albert was told the single dates of 18 and 19, it would have been easy for Albert without needing the month. But since Albert showed confusion at first, then Benard knew it wasn't any of those dates.
So we eliminate May and June. In the next months July and August, we decide to eliminate 14 since it cannot be any date appearing in these two months left.
Since we have just 3 dates left Linda, it cannot be a month with two dates since there is no further clue to use for elimination. So we automatically assume it is July with only 16 left in that date.
First we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
From the first statement, we know that Albert is sure that Bernard doesn’t know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn’t know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can’t know).
Since Albert subsequently can also be sure of the date, he must know it’s July. If it’s August, he can’t be sure as there is August 15 and 17.
The answer is July 16. Eliminate the unique dates thus eliminating May and June as months, eliminate the duplicate dates across the months, and the only unique date you have in a unique month is July 16.
may 15 cancel august 15 June 17 cancel august 17 July 14 cancel august 14 may 16 cancel July 16 we are left with may 19 and June 18 19+18=37/2 =18.5 the answer is may 19.
I hope i get a gift for this. First we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
From the first statement, we know that Albert is sure that Bernard doesn’t know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn’t know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can’t know).
Since Albert subsequently can also be sure of the date, he must know it’s July. If it’s August, he can’t be sure as there is August 15 and 17.
First we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
From the first statement, we know that Albert is sure that Bernard doesn't know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn't know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can't know).
Since Albert subsequently can also be sure of the date, he must know it's July. If it's August, he can't be sure as there is August 15 and 17.
Albert knows month, Bernard knows the date. Bernard will know if the birthday is on June 18 or May 19, because there are no other 18th or 19th. Albert knows for sure Bernard does not know implies the month is not May or June, otherwise there is a chance Bernard may know. Therefore the month is July or August.
Bernard at first doesn't know, but knows now. Therefore not July 14 or August 14, otherwise Bernard would still not know. That leaves us with July 16, August 15 and August 17.
Albert knows now. If it is August, Albert would still not know as there are 2 choices possible.
At first the question appears impossible to answer without a bit of extra information, but we know Cheryl has already told Albert the month of her birthday, and Bernard the day.
Each of the men does not know what the other has been told.
This allows reasoning to be used to begin to whittle down the number of options.
So, firstly, for Albert to be ‘certain’ that Bernard cannot know the answer – as suggested in the first statement he makes – we can deduct that the birthday is not in May or June.
This is because in the months of May and June there are numbers (dates) that only occur once across the four months – namely May 19 and June 18.
If Albert had been given May or June as the month, there is no way he could be certain that Bernard doesn’t know the birthday. Bernard, after all, might have been the number 18 or 19.
For Albert to be ‘certain’ that Bernard doesn’t know, Albert must have been given a month that does not contain one of these ‘unique’ dates – i.e. July or August.
Albert’s disclosure now gives Bernard the clue he needs, and says he now knows the birthday.
Bernard only knows the number of Cheryl’s birthday, but from Albert’s statement he has now also ruled out both May and June. This is because he realises Albert has ruled out May and June because of the ‘single number’ aspect above.
So there are now just five remaining dates – July 14, July 16, Aug 14, Aug 15, Aug 17 – and Bernard says he knows which is the birthday.
Because he now knows the date, we can whittle it down further to three dates by ruling out the numbers that appear in duplicate.
If Cheryl had told Bernard that her birthday fell on the 14th of the month, then he could not have worked out the date at this stage.
However, as he states that he now knows the date, we can rule out July 14 or August 14.
This leaves just three dates to choose from – July 16, Aug 15 and Aug 17.
Following Bernard’s statement, Albert is then apparently able to deduce the date of Cheryl’s birthday.
This means her birthday must be the only remaining date in the month he was originally told. Given that there are two dates left in August and one in July, it has to be the July date.
Albert knows the month while Bernard knows the day. Albert must have said Bernard does not know the date with certainty because the month Cheryl told him must have had only days that were repeated (I.e. months that have 14, 15, 16 and 17 and not contain 19 and 18). This eliminates May and June. Bernard caught on to Albert's logic that knew the month must either be July or August and the only reason he would have been able to deduce the birthday date from this would be if the date appeared only once in the months of July and August which is 17. Then Albert also caught on to Bernard's logic. Smart kids.
May 15 (i think), She tells Albert the month not the day and she tells Bernard the day not the month, since it was stated that she told them separately and respectively, it is safe to assume the months were for Albert and the dates were for Bernard. Also, reasoning why the listed dates were arranged in a ratio manner (3:2 & 2:3) rather than listed. So the answer is to look for the date that corresponds between two similar ratios which is May 15 and August 15, knowing Albert got the month and not the day & vice versa, the logical answer is May 15.
I don't think this is a maths question, its logic and reasoning.
May 15 (i think), She tells Albert the month not the day and she tells Bernard the day not the month, since it was stated that she told them separately and respectively, it is safe to assume the months were for Albert and the dates were for Bernard. Also, reasoning why the listed dates were arranged in a ratio manner (3:2 & 2:3) rather than listed. So the answer is to look for the date that corresponds between two similar ratios which is May 15 and August 15, knowing Albert got the month and not the day & vice versa, the logical answer is May 15.
I don't think this is a maths question, its logic and reasoning.
These logic puzzles mehn! Hvn't done this type of math in a lonngggg time. I think we shud focus on Math more in Naija. Its the bedrock of alot of disciplines and quite frankly more helpful in the future
Who mathematics don help????
ReplyDeleteLindaobserve it's hard
ReplyDeleteWho mathematics don help????
ReplyDeleteNot for a common driver like me :)
ReplyDeleteJuly 16
ReplyDeletenawa..this is quite difficult..and to say a nigerian mom was complaining about the kind of questions give to her primary ward..let her come and see the one that has leg
ReplyDeletewww.glowyshoe.blogspot.com
suck prick abeg
ReplyDeleteWAT KNDA ESSAY-LYK MATHS QUESTION IS DS??TOMJERRYSWIT
ReplyDeleteHmm! Leaked: Video of a slim Warri babe in hot sexcapade with three guys (Fast Download)
ReplyDeletesuck prick abeg
ReplyDeleteCorrection: It was for 14 year olds in Secondary School
ReplyDeletesuck prick abeg
ReplyDeleteLol, are these people for real? What kind of question is this?
ReplyDeleteIs nt a difficult question bt 4 a primary school, na wa o
ReplyDeleteQuestion for the gods
ReplyDeleteHmm
ReplyDeleteLeaked: Video of a slim Warri babe in hot sexcapade with three guys (Fast Download)
a.k.a EDWIN CHINEDU AZUBUKO said...
ReplyDelete.
Anything relating to maths count me out..
.
.
***CURRENTLY IN JUPITER***
HMm! Leaked: Video of a slim Warri babe in hot sexcapade with three guys (Fast Download)
ReplyDeletesuck my pr*ck
ReplyDeleteMay 19. That's the answer
ReplyDeletethis is no Maths question, I don't see no answer, it could be any of the 10 options.
ReplyDeletejuly 16th is the answer.
ReplyDelete00000000000000000000000 ..Linda you go go ask Cheryl o . We dey here dey suffer news about the Xenophobic attacks you dey tell us about Cheryl BDay. Abeg when you find the answer let me know so I can come chop cake on her Bday
ReplyDeleteMy daughter says its July 14th
ReplyDeleteCopied.
ReplyDeletejuly 16
ReplyDeleteLinda na wa oh...no options?
ReplyDeleteits july 16th
ReplyDeleteAugust 15th....
ReplyDeleteCheryl birthday is............may...june..july..august.. Dats d answer.
ReplyDeleteJuly 16
ReplyDeletelooool thiss was also sent to us by a teacher in my school..
ReplyDeletePeople have come up with Possible answers though buh me i think it's between May 19 and June 18....
buh also a student came up with evidence as to why he thinks it's July 16....
this quite logical though
Whew!!! Thank God I wasn't born in singapore
ReplyDeleteJuly 16!!!!
ReplyDeleteit looks like a probability question but like seriously times aren't that hard to make a young PRY pupil solve this.....like seriously
ReplyDeletehaaa
ReplyDeletei am just going to say may 19 coz thats my birthday
ReplyDeleteLinda u carry last for this the answer is already on BBC web site
ReplyDeleteNa craze?
ReplyDeleteIf Cheryl had told Bernard that her birthday fell on the 14th of the month, then he could not have worked out the date at this stage.
ReplyDeleteHowever, as he states that he now knows the date, we can rule out July 14 or August 14.
This leaves just three dates to chose from - July 16, Aug 15 and Aug 17.
Following Bernard's statement, Albert is then apparently able to deduce the date of Cheryl's birthday.
This means her birthday must be the only remaining date in the month he was originally told. Given that there are two dates left in August and one in July, it has to be the July date.
So the answer is July 16.
July 16th
ReplyDeleteJuly 16
ReplyDeleteMehnnnn
ReplyDeleteJuly 16. Thank me later.
ReplyDeleteNow I know why they always have funny looking heads.
ReplyDeleteIG: ALITTLEBITOFWORK
July 16
ReplyDeleteg.omashenu@gmail.com
44..SHEBI AM CORRECT lINDA
ReplyDeleteSOME PEOPLE ARE JUST SO VAIN...MEET RAJEE NANNESING THE LADY WHO GOT CEMENT INJECTED INTO HER CHEEK...BY QUACK DOCTOR
ABOMINATION...YOY WON'T BELIEVE THE SIZE OF LATE TUPAC'S EGGPLANT..MEHN I WEEP
A math professor explained the answer in BBC world news. Na process of elimination
ReplyDeleteJuly 16.
ReplyDeleteI hate this question with all my life.
Fuck the Teacher too.
July 16
ReplyDeleteSaw the answer on CNN already last night. July 16. I havent't taken time to, actually, solve it.
ReplyDeleteJuly 16
ReplyDeleteMay and June are ruled out by the first statement, as Albert knows that Bernard can't identify the month from his date so it is not 18/19. He can only know this because it is not May or June.
ReplyDeleteBernard can use Albert's statement, as we can, to rule out May and June - so his Day must be 14, 15, 16 or 17. Bernard knows that Albert couldn't previously rule out 14 but can now. So 15,16,17 left.
I'm afraid I took a shortcut rather than thinking and scanned upwards in my grid for "what's different" forgetting that Bernard's missing information is the month. So yes, 16 is the only remaining day that uniquely identifies a month
Ans is July 16
Here’s mine:
ReplyDeleteRemember, Albert is told either May, June, July or August.
Bernard is told either 14, 15, 16, 17, 18 or 19
Let’s go through it line by line.
Albert: I don’t know when Cheryl’s birthday is, but I know that Bernard doesn’t know too.
All Albert knows is the month, and every month has more than one possible date, so of course he doesn’t know when her birthday is. The first part of the sentence is redundant.
The only way that Bernard could know the date with a single number, however, would be if Cheryl had told him 18 or 19, since of the ten date options only these numbers appear once, as May 19 and June 18.
For Albert to know that Bernard does not know, Albert must therefore have been told July or August, since this rules out Bernard being told 18 or 19.
Line 2) Bernard: At first I don’t know when Cheryl’s birthday is, but now I know.
Bernard has deduced that Albert has either August or July. If he knows the full date, he must have been told 15, 16 or 17, since if he had been told 14 he would be none the wiser about whether the month was August or July. Each of 15, 16 and 17 only refers to one specific month, but 14 could be either month.
Line 3) Albert: Then I also know when Cheryl’s birthday is.
Albert has therefore deduced that the possible dates are July 16, Aug 15 and Aug 17. For him to now know, he must have been told July. Since if he had been told August, he would not know which date for certain is the birthday.
The answer, therefore is July 16.
Credit: http://www.theguardian.com/science/alexs-adventures-in-numberland/2015/apr/13/how-to-solve-albert-bernard-and-cheryls-birthday-maths-problem
answer is august 15year old
ReplyDeleteFirst we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
ReplyDeleteFrom the first statement, we know that Albert is sure that Bernard doesn't know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn't know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can't know).
Since Albert subsequently can also be sure of the date, he must know it's July. If it's August, he can't be sure as there is August 15 and 17.
So the answer is July 16.
august 15 years
ReplyDeleteMumu question..... Mtchew
ReplyDeleteIs May 19
ReplyDelete~Vavo Marker~
July 16, using the process of logic and elimination
ReplyDeleteThe answer is July 16th
ReplyDeleteLol, may 19
ReplyDeleteThe Answer is July 16.
ReplyDeleteThe question was also shown to us by our school
May 19
ReplyDelete~Vavoom Marker~
I cant think
ReplyDeleteHey!!! Beadlovers,
Ever heard of Cellini Peyote spiral, click on this link for details and tutorial.
cellini
august 15
ReplyDeleteCheryl's birthday is the same date she told the both of them
ReplyDeleteaugust 15
ReplyDeleteaugust 15
ReplyDeleteJuly 16!!
ReplyDeletewhich kain question be this one?
ReplyDeletelindalook!
which kain question be this one?
ReplyDeletelindalook!
which kain question be this one?
ReplyDeletelindalook!
which kain question be this one?
ReplyDeletelindalook!
august 15
ReplyDeleteJuly 16th.
ReplyDeleteNo doubts about it.
July19
ReplyDeleteIts probability. Total output is 10 and cherry's birthday will possibly be 1/10.
ReplyDeleteThe Answer is July 16.
ReplyDeleteJuly 16 Mofos
ReplyDeleteLol...dis wan don pass jamb question ooo.
ReplyDeleteJuly 16
ReplyDeleteJuly 16
ReplyDeleteChineke, this question is kinda hard for primary school kids. Its pure logic that gets you thinking and if you are not that smart you may not b able to figure it out.
ReplyDeleteAnyways the correct ans is july 16. Linda you can thank me later for the ans.
#streetwise#
Fuck sake wth is dis question got to do with maths
ReplyDeleteChineke, this question is kinda hard for primary school kids. Its pure logic that gets you thinking and if you are not that smart you may not b able to figure it out.
ReplyDeleteAnyways the correct ans is july 16. Linda you can thank me later for the ans.
#streetwise#
july 16
ReplyDeletejuly 16
ReplyDeletejuly 16
ReplyDeletejuly 16
ReplyDeleteYou use a probability of both Albert and Bernard knowing cherlys bday. But is much for primary school kids
ReplyDeleteThis can be maths na!! It doesn't make sense to me
ReplyDeleteThat awkward moment when nobody turns up for Cheryl's birthday party becos we don't know the date. Bye!
ReplyDeleteit's July 16
ReplyDeleteMe I no know oo.
ReplyDeleteCheryl ' s birthday should be August 17
ReplyDeleteIt's so stupid! I wouldn't even bother with it if my graduation depended on it.
ReplyDeleteI don't think this is a maths question but a question for witches and wizards. Or perhaps for guessers.
ReplyDeleteJULY 16
ReplyDeleteNone of the above
ReplyDeleteOnly Bernard and Albert know the date. So the birthday is cheryl birthday.
ReplyDeleteFirst we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
ReplyDeleteFrom the first statement, we know that Albert is sure that Bernard doesn’t know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn’t know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can’t know).
Since Albert subsequently can also be sure of the date, he must know it’s July. If it’s August, he can’t be sure as there is August 15 and 17.
So the answer is July 16.
It's tricky but I worked it out. The answer is July 16
ReplyDeleteThe day Cheryl was born is her birthday
ReplyDeleteAlthough the solution is fairly easy, the statements the boys make are contradictions. Good brain teaser tho.
ReplyDeleteif you know the ans pls say it cos it driving cr^^y.
ReplyDeleteBiko, lemme read comments. I can't crack my brain now, but the children dat solves dis must be little Einsteins. Linda take note!
ReplyDeleteBiko, lemme read comments. I can't crack my brain now, but the children dat solves dis must be little Einsteins. Linda take note!
ReplyDeleteBiko, lemme read comments. I can't crack my brain now, but the children dat solves dis must be little Einsteins. Linda take note!
ReplyDeleteBiko, lemme read comments. I can't crack my brain now, but the children dat solves dis must be little Einsteins. Linda take note!
ReplyDeleteBiko, lemme read comments. I can't crack my brain now, but the children dat solves dis must be little Einsteins. Linda take note!
ReplyDeleteMay 15
ReplyDeleteAlbert knows the month and bernard knows the date...simply english
ReplyDeleteJUly 16
ReplyDeleteJuly 16
ReplyDeleteStupid Question!
ReplyDeleteNmaaa
Stupid Question!
ReplyDeleteNmaaa
(JULY 21st) is my deduction afta much pattern observation!. P.S: If it's not correct, I am relocating to the Lagos Lagoon untill further notice. Ha!
ReplyDeleteThe answer is already on Aljazeera. A reporter already solved it.if you want to know the answer, watch Aljazeera.
ReplyDeleteNo idea
ReplyDeleteLemme guess august 15
The answer is July 16. The is my explanation.
ReplyDeleteThe days ranges from 14 to 19, with 18 and 19 appearing only once. So if Cheryls B-day is either 18 or 19 then Benard will know because Cheryl told him the day.
If Cheryl has told Albert her birth month was may or june, it is possible that her B-day will be June 18 or May 19. So if Albert is sure that Benard does not know means that Cheryls told Albert that her B-day is either August or July.
Benard did not know before, but how comes he knows now; after Albert has spoken.
I have 5 dates left in July and August from my solution, Thats 14 to 17 with 14 appearing two times.
(July 14, July 16, August 14, August 15, August 17).
So Benard will not know the date of Cheryl B-day if she told him 14.
So the day is not 14.
I have 3 dates left
(July 16, August 15, August 17).
Since Benard spoke, Albert now knows Cheryl B-day, If Cheryl had told Albert her B-day was in August then Albert would not know because there are two possible dates in August ..
So The Answer Is JULY 16.
Albert knows the month and Bernard knows the day, and at first they dont know the birthday, it's safe to knock off the months of may and June because since Bernard knows the day, it will be easy to choose may 19 or June 18 because the numbers 18 and 19 appear just once in the days given.
ReplyDeleteBernard now says he knows the birthday, which strikes of July 14 and august 14. Because if he was given 14 as the day he will still be confused as there is July 14 and august 14, knowing full well he was given just the day.
Lastly, Albert says he knows the birthday too, which strikes of august because there are 3 days in august and would have still been confused, as he wasn't given the day and may have to choose between the three days in august.
What is left is July 16th. That's Cheryl's birthday!!
July 16. Google is your friend
ReplyDeleteNa wah ooo
ReplyDeleteJuly 16.
ReplyDeleteExplanation available on request.
no idea... but I trust a LIB reader to solve it
ReplyDeleteI think the answer is July 16th
ReplyDeleteNot today biko. Not after d one I just finished battling wit
ReplyDeleteJuly 16---answer arrived at after careful logical and critical elimination
ReplyDeleteJuly 16---answer arrived at after careful logical and critical elimination
ReplyDeleteMath question and no one has anything to say! Shows what we value as a country.
ReplyDeleteCheryl's birthday is July 16.
Hahaha!!! Saw it online too. It's a trick question. The answer is "there's no answer". Lool
ReplyDeleteWalahi there is no answer!! if there is..........It should be May 19
ReplyDeleteJuly 16th
ReplyDeleteBernard can only know initially if he has been given a date number which is unique namely 18th or 19th
But you can rule out May and June (the months containing 18th and 19th) immediately because Albert says Benard cannot know. So it must be July or August and based on this
Based on this , Bernard says he now knows. That means it has to be July 16th, August 15th or August 17th. if it was 14th, he would need to know the month to know the date so we can rule out 14th
Based on this Albert says he too knows, which means It cannot be August 15th or 17th (if it were, he would need to know the date number as well). So it must be July 16th
phew
pry schl????????????????? wat oya mathematician ansa abeg
ReplyDeleteJune 18
ReplyDeleteFirst we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
ReplyDeleteFrom the first statement, we know that Albert is sure that Bernard doesn’t know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn’t know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can’t know).
Since Albert subsequently can also be sure of the date, he must know it’s July. If it’s August, he can’t be sure as there is August 15 and 17.
So the answer is July 16.
The day she was born.:) 13-12-12
ReplyDelete(16-15)=1 (19-16)=3-->13
(18-17)=1 next line to confuse
(16-14)=2-->12
(15-14)=1 (17-15)=2-->12
The answer is July 16, after eliminating logically.
ReplyDeleteFirst, if Albert was told the single dates of 18 and 19, it would have been easy for Albert without needing the month. But since Albert showed confusion at first, then Benard knew it wasn't any of those dates.
So we eliminate May and June. In the next months July and August, we decide to eliminate 14 since it cannot be any date appearing in these two months left.
Since we have just 3 dates left Linda, it cannot be a month with two dates since there is no further clue to use for elimination. So we automatically assume it is July with only 16 left in that date.
So it is July 16.
linda its july 16
ReplyDeleteAugust 17
ReplyDeleteFirst we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
ReplyDeleteFrom the first statement, we know that Albert is sure that Bernard doesn’t know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn’t know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can’t know).
Since Albert subsequently can also be sure of the date, he must know it’s July. If it’s August, he can’t be sure as there is August 15 and 17.
So the answer is July 16.
The answer is July 16. Eliminate the unique dates thus eliminating May and June as months, eliminate the duplicate dates across the months, and the only unique date you have in a unique month is July 16.
ReplyDeleteCheryl is dead
ReplyDeletemay 15 cancel august 15
ReplyDeleteJune 17 cancel august 17
July 14 cancel august 14
may 16 cancel July 16
we are left with may 19 and June 18
19+18=37/2
=18.5
the answer is may 19.
onyigift75@yahoo.com
Ridiculous!.. Makes no sense to me.
ReplyDeleteUnless, her BD is on all ten dates.
May 14TH
ReplyDeletemeenah_wakil on instagram
May 14TH
ReplyDeletemeenah_wakil on instagram
I hope i get a gift for this.
ReplyDeleteFirst we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
From the first statement, we know that Albert is sure that Bernard doesn’t know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn’t know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can’t know).
Since Albert subsequently can also be sure of the date, he must know it’s July. If it’s August, he can’t be sure as there is August 15 and 17.
So the answer is July 16.
email:ephemereal2000 at gmail dot com
D solution, and answer to dis simple question is Bernard, and Albert knw d date to her birthday. So pls re-direct d question to them.
ReplyDeleteTODAY.
ReplyDeleteObey, we font know wat cherlyn told Albert nd Bernard? We be magicians?
ReplyDeleteFirst we need to figure out if Albert knows the month or the day. If he knows the day, then there is no chance that Bernard knows the birthday, so it must be that Albert knows the month.
ReplyDeleteFrom the first statement, we know that Albert is sure that Bernard doesn't know the birthday, so May and June should be ruled out (the day 19 only appears in May and the day 18 only appears in June). In other words, if Albert had May or June, then he cannot be sure that Bernard doesn't know, since Bernard could have had 18 or 19.
Following that statement, Bernard knows that May and June are ruled out.
Then, Bernard is able to know which month it is. So it must be either July 16, August 15 and August 17 (not 14th as then he can't know).
Since Albert subsequently can also be sure of the date, he must know it's July. If it's August, he can't be sure as there is August 15 and 17.
So the answer is July 16.
Obey, we font know wat cherlyn told Albert nd Bernard? We be magicians?
ReplyDeleteI be witch ni
ReplyDeleteWtf... d d teacher dat gave dem dat question shld solve it demselves
ReplyDeleteJune 18.
ReplyDeleteJune 18.
ReplyDeleteMay 19th
ReplyDelete*sipping kunu n passing by*
ReplyDeleteMay 15, the answer is within the question
ReplyDeleteAugust 17
ReplyDeleteAlbert knows month, Bernard knows the date. Bernard will know if the birthday is on June 18 or May 19, because there are no other 18th or 19th.
ReplyDeleteAlbert knows for sure Bernard does not know implies the month is not May or June, otherwise there is a chance Bernard may know. Therefore the month is July or August.
Bernard at first doesn't know, but knows now. Therefore not July 14 or August 14, otherwise Bernard would still not know. That leaves us with July 16, August 15 and August 17.
Albert knows now. If it is August, Albert would still not know as there are 2 choices possible.
Hence the answer is July 16.
The first date she gave,
ReplyDeleteMay 15/A month from today.
Mike
April 2nd
ReplyDeleteJuly 16
ReplyDeleteAt first the question appears impossible to answer without a bit of extra information, but we know Cheryl has already told Albert the month of her birthday, and Bernard the day.
ReplyDeleteEach of the men does not know what the other has been told.
This allows reasoning to be used to begin to whittle down the number of options.
So, firstly, for Albert to be ‘certain’ that Bernard cannot know the answer – as suggested in the first statement he makes – we can deduct that the birthday is not in May or June.
This is because in the months of May and June there are numbers (dates) that only occur once across the four months – namely May 19 and June 18.
If Albert had been given May or June as the month, there is no way he could be certain that Bernard doesn’t know the birthday. Bernard, after all, might have been the number 18 or 19.
For Albert to be ‘certain’ that Bernard doesn’t know, Albert must have been given a month that does not contain one of these ‘unique’ dates – i.e. July or August.
Albert’s disclosure now gives Bernard the clue he needs, and says he now knows the birthday.
Bernard only knows the number of Cheryl’s birthday, but from Albert’s statement he has now also ruled out both May and June. This is because he realises Albert has ruled out May and June because of the ‘single number’ aspect above.
So there are now just five remaining dates – July 14, July 16, Aug 14, Aug 15, Aug 17 – and Bernard says he knows which is the birthday.
Because he now knows the date, we can whittle it down further to three dates by ruling out the numbers that appear in duplicate.
If Cheryl had told Bernard that her birthday fell on the 14th of the month, then he could not have worked out the date at this stage.
However, as he states that he now knows the date, we can rule out July 14 or August 14.
This leaves just three dates to choose from – July 16, Aug 15 and Aug 17.
Following Bernard’s statement, Albert is then apparently able to deduce the date of Cheryl’s birthday.
This means her birthday must be the only remaining date in the month he was originally told. Given that there are two dates left in August and one in July, it has to be the July date.
So the answer is July 16.
Get your facts right, it's a maths question for 14 years and they should be in secondary school not primary school.
ReplyDeleteIs that maths?
ReplyDeleteJune 18. Albert knows the month which could be any of the four months. But his partners knows the date. There is just one month south 18
ReplyDeleteThe answer is May 19,dont thinik it too deep. think like a kid and u'l easily see it. Wizzzzz
ReplyDeleteJuly 16th I did expo. LOOL!
ReplyDeleteThe answer is August 17.
ReplyDeleteAlbert knows the month while Bernard knows the day. Albert must have said Bernard does not know the date with certainty because the month Cheryl told him must have had only days that were repeated (I.e. months that have 14, 15, 16 and 17 and not contain 19 and 18). This eliminates May and June.
Bernard caught on to Albert's logic that knew the month must either be July or August and the only reason he would have been able to deduce the birthday date from this would be if the date appeared only once in the months of July and August which is 17.
Then Albert also caught on to Bernard's logic.
Smart kids.
May 15 (i think), She tells Albert the month not the day and she tells Bernard the day not the month, since it was stated that she told them separately and respectively, it is safe to assume the months were for Albert and the dates were for Bernard. Also, reasoning why the listed dates were arranged in a ratio manner (3:2 & 2:3) rather than listed. So the answer is to look for the date that corresponds between two similar ratios which is May 15 and August 15, knowing Albert got the month and not the day & vice versa, the logical answer is May 15.
ReplyDeleteI don't think this is a maths question, its logic and reasoning.
May 15 (i think), She tells Albert the month not the day and she tells Bernard the day not the month, since it was stated that she told them separately and respectively, it is safe to assume the months were for Albert and the dates were for Bernard. Also, reasoning why the listed dates were arranged in a ratio manner (3:2 & 2:3) rather than listed. So the answer is to look for the date that corresponds between two similar ratios which is May 15 and August 15, knowing Albert got the month and not the day & vice versa, the logical answer is May 15.
ReplyDeleteI don't think this is a maths question, its logic and reasoning.
This is a math test for Harry Potter, witches and wizards. Na dem be mind readers
ReplyDeleteThese logic puzzles mehn! Hvn't done this type of math in a lonngggg time. I think we shud focus on Math more in Naija. Its the bedrock of alot of disciplines and quite frankly more helpful in the future
ReplyDeleteJuly 16
ReplyDeleteits either june 18 or may 19
ReplyDeleteHer birthday is on " June 12"
ReplyDeleteAugust 17
ReplyDeleteAugust 17
ReplyDeleteBiko, this ain't maths
ReplyDeleteLinda its may 19. Because 19 is the only day that doesn't have another month with it. May only. Others cancel out each other.
ReplyDeleteBetween May 15 to Aug 17
ReplyDeleteHas to be July 16, if he then knew after he spoke
ReplyDeleteThe Answer is July 16
ReplyDeletemay 19
ReplyDeleteiamsegun
fasegz@gmail.com
July 16th
ReplyDeletethe answer is July 16th....
ReplyDeleteJuly 16 is d answer
ReplyDeletecherly's birthday is July 16th
ReplyDeleteFrom the conversation and the dates, Cheryl's birthday is May 17
ReplyDeleteFrom the conversation and the dates, Cheryl's birthday is May 17
ReplyDeleteFrom the conversation and the dates, Cheryl's birthday is May 17
ReplyDeleteFrom the conversation and the dates, Cheryl's birthday is May 17
ReplyDeleteMay 19
ReplyDeleteMay 19th
ReplyDeleteSimple logic .........her bday is 16th July.Shikenah.
ReplyDeleteIt's "MATH" Nigeria, NOT "MATHS". Just like its "STUFF" and NOT "STUFFS" sheesh
ReplyDelete